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- *DECK CPOSL
- SUBROUTINE CPOSL (A, LDA, N, B)
- C***BEGIN PROLOGUE CPOSL
- C***PURPOSE Solve the complex Hermitian positive definite linear system
- C using the factors computed by CPOCO or CPOFA.
- C***LIBRARY SLATEC (LINPACK)
- C***CATEGORY D2D1B
- C***TYPE COMPLEX (SPOSL-S, DPOSL-D, CPOSL-C)
- C***KEYWORDS LINEAR ALGEBRA, LINPACK, MATRIX, POSITIVE DEFINITE, SOLVE
- C***AUTHOR Moler, C. B., (U. of New Mexico)
- C***DESCRIPTION
- C
- C CPOSL solves the COMPLEX Hermitian positive definite system
- C A * X = B
- C using the factors computed by CPOCO or CPOFA.
- C
- C On Entry
- C
- C A COMPLEX(LDA, N)
- C the output from CPOCO or CPOFA.
- C
- C LDA INTEGER
- C the leading dimension of the array A .
- C
- C N INTEGER
- C the order of the matrix A .
- C
- C B COMPLEX(N)
- C the right hand side vector.
- C
- C On Return
- C
- C B the solution vector X .
- C
- C Error Condition
- C
- C A division by zero will occur if the input factor contains
- C a zero on the diagonal. Technically this indicates
- C singularity but it is usually caused by improper subroutine
- C arguments. It will not occur if the subroutines are called
- C correctly and INFO .EQ. 0 .
- C
- C To compute INVERSE(A) * C where C is a matrix
- C with P columns
- C CALL CPOCO(A,LDA,N,RCOND,Z,INFO)
- C IF (RCOND is too small .OR. INFO .NE. 0) GO TO ...
- C DO 10 J = 1, P
- C CALL CPOSL(A,LDA,N,C(1,J))
- C 10 CONTINUE
- C
- C***REFERENCES J. J. Dongarra, J. R. Bunch, C. B. Moler, and G. W.
- C Stewart, LINPACK Users' Guide, SIAM, 1979.
- C***ROUTINES CALLED CAXPY, CDOTC
- C***REVISION HISTORY (YYMMDD)
- C 780814 DATE WRITTEN
- C 890831 Modified array declarations. (WRB)
- C 890831 REVISION DATE from Version 3.2
- C 891214 Prologue converted to Version 4.0 format. (BAB)
- C 900326 Removed duplicate information from DESCRIPTION section.
- C (WRB)
- C 920501 Reformatted the REFERENCES section. (WRB)
- C***END PROLOGUE CPOSL
- INTEGER LDA,N
- COMPLEX A(LDA,*),B(*)
- C
- COMPLEX CDOTC,T
- INTEGER K,KB
- C
- C SOLVE CTRANS(R)*Y = B
- C
- C***FIRST EXECUTABLE STATEMENT CPOSL
- DO 10 K = 1, N
- T = CDOTC(K-1,A(1,K),1,B(1),1)
- B(K) = (B(K) - T)/A(K,K)
- 10 CONTINUE
- C
- C SOLVE R*X = Y
- C
- DO 20 KB = 1, N
- K = N + 1 - KB
- B(K) = B(K)/A(K,K)
- T = -B(K)
- CALL CAXPY(K-1,T,A(1,K),1,B(1),1)
- 20 CONTINUE
- RETURN
- END
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