relibc_openlibm/slatec/passb3.f

*DECK PASSB3
      SUBROUTINE PASSB3 (IDO, L1, CC, CH, WA1, WA2)
C***BEGIN PROLOGUE  PASSB3
C***SUBSIDIARY
C***PURPOSE  Calculate the fast Fourier transform of subvectors of
C            length three.
C***LIBRARY   SLATEC (FFTPACK)
C***TYPE      SINGLE PRECISION (PASSB3-S)
C***AUTHOR  Swarztrauber, P. N., (NCAR)
C***ROUTINES CALLED  (NONE)
C***REVISION HISTORY  (YYMMDD)
C   790601  DATE WRITTEN
C   830401  Modified to use SLATEC library source file format.
C   860115  Modified by Ron Boisvert to adhere to Fortran 77 by
C           (a) changing dummy array size declarations (1) to (*),
C           (b) changing definition of variable TAUI by using
C               FORTRAN intrinsic function SQRT instead of a DATA
C               statement.
C   881128  Modified by Dick Valent to meet prologue standards.
C   890831  Modified array declarations.  (WRB)
C   891214  Prologue converted to Version 4.0 format.  (BAB)
C   900402  Added TYPE section.  (WRB)
C***END PROLOGUE  PASSB3
      DIMENSION CC(IDO,3,*), CH(IDO,L1,3), WA1(*), WA2(*)
C***FIRST EXECUTABLE STATEMENT  PASSB3
      TAUR = -.5
      TAUI = .5*SQRT(3.)
      IF (IDO .NE. 2) GO TO 102
      DO 101 K=1,L1
         TR2 = CC(1,2,K)+CC(1,3,K)
         CR2 = CC(1,1,K)+TAUR*TR2
         CH(1,K,1) = CC(1,1,K)+TR2
         TI2 = CC(2,2,K)+CC(2,3,K)
         CI2 = CC(2,1,K)+TAUR*TI2
         CH(2,K,1) = CC(2,1,K)+TI2
         CR3 = TAUI*(CC(1,2,K)-CC(1,3,K))
         CI3 = TAUI*(CC(2,2,K)-CC(2,3,K))
         CH(1,K,2) = CR2-CI3
         CH(1,K,3) = CR2+CI3
         CH(2,K,2) = CI2+CR3
         CH(2,K,3) = CI2-CR3
  101 CONTINUE
      RETURN
  102 IF(IDO/2.LT.L1) GO TO 105
      DO 104 K=1,L1
CDIR$ IVDEP
         DO 103 I=2,IDO,2
            TR2 = CC(I-1,2,K)+CC(I-1,3,K)
            CR2 = CC(I-1,1,K)+TAUR*TR2
            CH(I-1,K,1) = CC(I-1,1,K)+TR2
            TI2 = CC(I,2,K)+CC(I,3,K)
            CI2 = CC(I,1,K)+TAUR*TI2
            CH(I,K,1) = CC(I,1,K)+TI2
            CR3 = TAUI*(CC(I-1,2,K)-CC(I-1,3,K))
            CI3 = TAUI*(CC(I,2,K)-CC(I,3,K))
            DR2 = CR2-CI3
            DR3 = CR2+CI3
            DI2 = CI2+CR3
            DI3 = CI2-CR3
            CH(I,K,2) = WA1(I-1)*DI2+WA1(I)*DR2
            CH(I-1,K,2) = WA1(I-1)*DR2-WA1(I)*DI2
            CH(I,K,3) = WA2(I-1)*DI3+WA2(I)*DR3
            CH(I-1,K,3) = WA2(I-1)*DR3-WA2(I)*DI3
  103    CONTINUE
  104 CONTINUE
      RETURN
  105 DO 107 I=2,IDO,2
CDIR$ IVDEP
         DO 106 K=1,L1
            TR2 = CC(I-1,2,K)+CC(I-1,3,K)
            CR2 = CC(I-1,1,K)+TAUR*TR2
            CH(I-1,K,1) = CC(I-1,1,K)+TR2
            TI2 = CC(I,2,K)+CC(I,3,K)
            CI2 = CC(I,1,K)+TAUR*TI2
            CH(I,K,1) = CC(I,1,K)+TI2
            CR3 = TAUI*(CC(I-1,2,K)-CC(I-1,3,K))
            CI3 = TAUI*(CC(I,2,K)-CC(I,3,K))
            DR2 = CR2-CI3
            DR3 = CR2+CI3
            DI2 = CI2+CR3
            DI3 = CI2-CR3
            CH(I,K,2) = WA1(I-1)*DI2+WA1(I)*DR2
            CH(I-1,K,2) = WA1(I-1)*DR2-WA1(I)*DI2
            CH(I,K,3) = WA2(I-1)*DI3+WA2(I)*DR3
            CH(I-1,K,3) = WA2(I-1)*DR3-WA2(I)*DI3
  106    CONTINUE
  107 CONTINUE
      RETURN
      END