relibc_openlibm/slatec/passb4.f

*DECK PASSB4
      SUBROUTINE PASSB4 (IDO, L1, CC, CH, WA1, WA2, WA3)
C***BEGIN PROLOGUE  PASSB4
C***SUBSIDIARY
C***PURPOSE  Calculate the fast Fourier transform of subvectors of
C            length four.
C***LIBRARY   SLATEC (FFTPACK)
C***TYPE      SINGLE PRECISION (PASSB4-S)
C***AUTHOR  Swarztrauber, P. N., (NCAR)
C***ROUTINES CALLED  (NONE)
C***REVISION HISTORY  (YYMMDD)
C   790601  DATE WRITTEN
C   830401  Modified to use SLATEC library source file format.
C   860115  Modified by Ron Boisvert to adhere to Fortran 77 by
C           changing dummy array size declarations (1) to (*).
C   881128  Modified by Dick Valent to meet prologue standards.
C   890831  Modified array declarations.  (WRB)
C   891214  Prologue converted to Version 4.0 format.  (BAB)
C   900402  Added TYPE section.  (WRB)
C***END PROLOGUE  PASSB4
      DIMENSION CC(IDO,4,*), CH(IDO,L1,4), WA1(*), WA2(*), WA3(*)
C***FIRST EXECUTABLE STATEMENT  PASSB4
      IF (IDO .NE. 2) GO TO 102
      DO 101 K=1,L1
         TI1 = CC(2,1,K)-CC(2,3,K)
         TI2 = CC(2,1,K)+CC(2,3,K)
         TR4 = CC(2,4,K)-CC(2,2,K)
         TI3 = CC(2,2,K)+CC(2,4,K)
         TR1 = CC(1,1,K)-CC(1,3,K)
         TR2 = CC(1,1,K)+CC(1,3,K)
         TI4 = CC(1,2,K)-CC(1,4,K)
         TR3 = CC(1,2,K)+CC(1,4,K)
         CH(1,K,1) = TR2+TR3
         CH(1,K,3) = TR2-TR3
         CH(2,K,1) = TI2+TI3
         CH(2,K,3) = TI2-TI3
         CH(1,K,2) = TR1+TR4
         CH(1,K,4) = TR1-TR4
         CH(2,K,2) = TI1+TI4
         CH(2,K,4) = TI1-TI4
  101 CONTINUE
      RETURN
  102 IF(IDO/2.LT.L1) GO TO 105
      DO 104 K=1,L1
CDIR$ IVDEP
         DO 103 I=2,IDO,2
            TI1 = CC(I,1,K)-CC(I,3,K)
            TI2 = CC(I,1,K)+CC(I,3,K)
            TI3 = CC(I,2,K)+CC(I,4,K)
            TR4 = CC(I,4,K)-CC(I,2,K)
            TR1 = CC(I-1,1,K)-CC(I-1,3,K)
            TR2 = CC(I-1,1,K)+CC(I-1,3,K)
            TI4 = CC(I-1,2,K)-CC(I-1,4,K)
            TR3 = CC(I-1,2,K)+CC(I-1,4,K)
            CH(I-1,K,1) = TR2+TR3
            CR3 = TR2-TR3
            CH(I,K,1) = TI2+TI3
            CI3 = TI2-TI3
            CR2 = TR1+TR4
            CR4 = TR1-TR4
            CI2 = TI1+TI4
            CI4 = TI1-TI4
            CH(I-1,K,2) = WA1(I-1)*CR2-WA1(I)*CI2
            CH(I,K,2) = WA1(I-1)*CI2+WA1(I)*CR2
            CH(I-1,K,3) = WA2(I-1)*CR3-WA2(I)*CI3
            CH(I,K,3) = WA2(I-1)*CI3+WA2(I)*CR3
            CH(I-1,K,4) = WA3(I-1)*CR4-WA3(I)*CI4
            CH(I,K,4) = WA3(I-1)*CI4+WA3(I)*CR4
  103    CONTINUE
  104 CONTINUE
      RETURN
  105 DO 107 I=2,IDO,2
CDIR$ IVDEP
         DO 106 K=1,L1
            TI1 = CC(I,1,K)-CC(I,3,K)
            TI2 = CC(I,1,K)+CC(I,3,K)
            TI3 = CC(I,2,K)+CC(I,4,K)
            TR4 = CC(I,4,K)-CC(I,2,K)
            TR1 = CC(I-1,1,K)-CC(I-1,3,K)
            TR2 = CC(I-1,1,K)+CC(I-1,3,K)
            TI4 = CC(I-1,2,K)-CC(I-1,4,K)
            TR3 = CC(I-1,2,K)+CC(I-1,4,K)
            CH(I-1,K,1) = TR2+TR3
            CR3 = TR2-TR3
            CH(I,K,1) = TI2+TI3
            CI3 = TI2-TI3
            CR2 = TR1+TR4
            CR4 = TR1-TR4
            CI2 = TI1+TI4
            CI4 = TI1-TI4
            CH(I-1,K,2) = WA1(I-1)*CR2-WA1(I)*CI2
            CH(I,K,2) = WA1(I-1)*CI2+WA1(I)*CR2
            CH(I-1,K,3) = WA2(I-1)*CR3-WA2(I)*CI3
            CH(I,K,3) = WA2(I-1)*CI3+WA2(I)*CR3
            CH(I-1,K,4) = WA3(I-1)*CR4-WA3(I)*CI4
            CH(I,K,4) = WA3(I-1)*CI4+WA3(I)*CR4
  106    CONTINUE
  107 CONTINUE
      RETURN
      END