1234567891011121314151617181920212223242526272829303132333435363738394041424344454647484950515253545556 |
- *DECK PASSF2
- SUBROUTINE PASSF2 (IDO, L1, CC, CH, WA1)
- C***BEGIN PROLOGUE PASSF2
- C***SUBSIDIARY
- C***PURPOSE Calculate the fast Fourier transform of subvectors of
- C length two.
- C***LIBRARY SLATEC (FFTPACK)
- C***TYPE SINGLE PRECISION (PASSF2-S)
- C***AUTHOR Swarztrauber, P. N., (NCAR)
- C***ROUTINES CALLED (NONE)
- C***REVISION HISTORY (YYMMDD)
- C 790601 DATE WRITTEN
- C 830401 Modified to use SLATEC library source file format.
- C 860115 Modified by Ron Boisvert to adhere to Fortran 77 by
- C changing dummy array size declarations (1) to (*).
- C 881128 Modified by Dick Valent to meet prologue standards.
- C 890831 Modified array declarations. (WRB)
- C 891214 Prologue converted to Version 4.0 format. (BAB)
- C 900402 Added TYPE section. (WRB)
- C***END PROLOGUE PASSF2
- DIMENSION CC(IDO,2,*), CH(IDO,L1,2), WA1(*)
- C***FIRST EXECUTABLE STATEMENT PASSF2
- IF (IDO .GT. 2) GO TO 102
- DO 101 K=1,L1
- CH(1,K,1) = CC(1,1,K)+CC(1,2,K)
- CH(1,K,2) = CC(1,1,K)-CC(1,2,K)
- CH(2,K,1) = CC(2,1,K)+CC(2,2,K)
- CH(2,K,2) = CC(2,1,K)-CC(2,2,K)
- 101 CONTINUE
- RETURN
- 102 IF(IDO/2.LT.L1) GO TO 105
- DO 104 K=1,L1
- CDIR$ IVDEP
- DO 103 I=2,IDO,2
- CH(I-1,K,1) = CC(I-1,1,K)+CC(I-1,2,K)
- TR2 = CC(I-1,1,K)-CC(I-1,2,K)
- CH(I,K,1) = CC(I,1,K)+CC(I,2,K)
- TI2 = CC(I,1,K)-CC(I,2,K)
- CH(I,K,2) = WA1(I-1)*TI2-WA1(I)*TR2
- CH(I-1,K,2) = WA1(I-1)*TR2+WA1(I)*TI2
- 103 CONTINUE
- 104 CONTINUE
- RETURN
- 105 DO 107 I=2,IDO,2
- CDIR$ IVDEP
- DO 106 K=1,L1
- CH(I-1,K,1) = CC(I-1,1,K)+CC(I-1,2,K)
- TR2 = CC(I-1,1,K)-CC(I-1,2,K)
- CH(I,K,1) = CC(I,1,K)+CC(I,2,K)
- TI2 = CC(I,1,K)-CC(I,2,K)
- CH(I,K,2) = WA1(I-1)*TI2-WA1(I)*TR2
- CH(I-1,K,2) = WA1(I-1)*TR2+WA1(I)*TI2
- 106 CONTINUE
- 107 CONTINUE
- RETURN
- END
|