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- *DECK SSCAL
- SUBROUTINE SSCAL (N, SA, SX, INCX)
- C***BEGIN PROLOGUE SSCAL
- C***PURPOSE Multiply a vector by a constant.
- C***LIBRARY SLATEC (BLAS)
- C***CATEGORY D1A6
- C***TYPE SINGLE PRECISION (SSCAL-S, DSCAL-D, CSCAL-C)
- C***KEYWORDS BLAS, LINEAR ALGEBRA, SCALE, VECTOR
- C***AUTHOR Lawson, C. L., (JPL)
- C Hanson, R. J., (SNLA)
- C Kincaid, D. R., (U. of Texas)
- C Krogh, F. T., (JPL)
- C***DESCRIPTION
- C
- C B L A S Subprogram
- C Description of Parameters
- C
- C --Input--
- C N number of elements in input vector(s)
- C SA single precision scale factor
- C SX single precision vector with N elements
- C INCX storage spacing between elements of SX
- C
- C --Output--
- C SX single precision result (unchanged if N .LE. 0)
- C
- C Replace single precision SX by single precision SA*SX.
- C For I = 0 to N-1, replace SX(IX+I*INCX) with SA * SX(IX+I*INCX),
- C where IX = 1 if INCX .GE. 0, else IX = 1+(1-N)*INCX.
- C
- C***REFERENCES C. L. Lawson, R. J. Hanson, D. R. Kincaid and F. T.
- C Krogh, Basic linear algebra subprograms for Fortran
- C usage, Algorithm No. 539, Transactions on Mathematical
- C Software 5, 3 (September 1979), pp. 308-323.
- C***ROUTINES CALLED (NONE)
- C***REVISION HISTORY (YYMMDD)
- C 791001 DATE WRITTEN
- C 890831 Modified array declarations. (WRB)
- C 890831 REVISION DATE from Version 3.2
- C 891214 Prologue converted to Version 4.0 format. (BAB)
- C 900821 Modified to correct problem with a negative increment.
- C (WRB)
- C 920501 Reformatted the REFERENCES section. (WRB)
- C***END PROLOGUE SSCAL
- REAL SA, SX(*)
- INTEGER I, INCX, IX, M, MP1, N
- C***FIRST EXECUTABLE STATEMENT SSCAL
- IF (N .LE. 0) RETURN
- IF (INCX .EQ. 1) GOTO 20
- C
- C Code for increment not equal to 1.
- C
- IX = 1
- IF (INCX .LT. 0) IX = (-N+1)*INCX + 1
- DO 10 I = 1,N
- SX(IX) = SA*SX(IX)
- IX = IX + INCX
- 10 CONTINUE
- RETURN
- C
- C Code for increment equal to 1.
- C
- C Clean-up loop so remaining vector length is a multiple of 5.
- C
- 20 M = MOD(N,5)
- IF (M .EQ. 0) GOTO 40
- DO 30 I = 1,M
- SX(I) = SA*SX(I)
- 30 CONTINUE
- IF (N .LT. 5) RETURN
- 40 MP1 = M + 1
- DO 50 I = MP1,N,5
- SX(I) = SA*SX(I)
- SX(I+1) = SA*SX(I+1)
- SX(I+2) = SA*SX(I+2)
- SX(I+3) = SA*SX(I+3)
- SX(I+4) = SA*SX(I+4)
- 50 CONTINUE
- RETURN
- END
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